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2p^2=5p+6
We move all terms to the left:
2p^2-(5p+6)=0
We get rid of parentheses
2p^2-5p-6=0
a = 2; b = -5; c = -6;
Δ = b2-4ac
Δ = -52-4·2·(-6)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{73}}{2*2}=\frac{5-\sqrt{73}}{4} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{73}}{2*2}=\frac{5+\sqrt{73}}{4} $
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